March 19th will be forever remembered as an historic day at Melbourne’s Eastwood Golf Club. On that fateful Saturday, an amazing event occured– one that has never happened before: three people scored an Ace on the same hole, on the same day. Two of those people were even in the same group!
It all happened on the 137-metre par-3 14th hole. Dragan Milosevic was the first to achieve the feat, playing in the morning group. Marking a triumphant “1″ on the card, Dragan was, needless to say, extremely confident he had sewn up the “Nearest the Pin” prize for the day.
But two afternoon players, Lance Robinson and Lindsay Howard, quickly dashed Dragan’s hopes, as they each scored aces of their own on the hole, achieving every golfer’s dream and giving the club an unprecedented three aces in one day.
What’s even more unique is that Lance and Lindsay were playing partners (in a group of 4) and were scoring each other’s card.
“It was quite unique to see two 1′s on the cards,” Lance told Inside Golf.
“We have never heard of this happening before. It has created quite a bit of fun and excitement around the club.”
Fittingly, all three players shared in the ball prize for nearest the pin. The club also awarded each player a hole-in-one trophy, a special tie, a couple of golf balls and free drinks for the members.
The odds of making a hole-in-one vary greatly, depending on the source and the calculation method. According to various articles and Hole-in-One Insurance agencies in the US, for an amateur to score an ace on a standard 150-yard hole, the probability is anywhere from 1 in 10,000 to 1 in 45,000 (this number is significantly lower for professional golfers).
But two players from the same foursome acing the same hole is something along the magnitude of 17 million to 1, according to www.nationalholeinoneregistry.com. Despite our research, we cannot find an estimate of the odds of three aces on the same hole, on the same day, with two players in the same foursome. (Can someone get us an abacus?)
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